# Python Program to Find Armstrong Number between an Interval

In this tutorial, we are going to learn how to find **Armstrong Number between an interval in Python**. It is very simple if we know what is Armstrong Number. Let’s see

## Find Armstrong Number between an Interval in Python

**Armstrong Number** can be defined as the number is equal to the sum of **Nth** power of each digit in that number. Where **N** is number of digits in that number.

abcd... = pow(a,n) + pow(b,n) + pow(c,n) + pow(d,n) + ....

**For example:** 153 1*1*1 + 5*5*5 + 3*3*3= 153 so it is Armstrong Number.

16 1*1 + 6*6 = 37 so it is not an Armstrong Number.

x=int(input("lower limit: ")) y=int(input("upper limit: ")) print("Armstrong Numbers are: ") for Number in range(x,y): digits=0 temp=Number while temp>0: # no of digits digits=digits+1 temp=temp//10 sum=0 temp=Number while temp>0: # calculate armstrong number last_digit=temp%10 sum=sum+(last_digit**digits) temp=temp//10 if Number == sum: print(Number)

### Code Explanation:

User has to enter two values lower limit and upper limit. Loop traversal from the lower limit to the upper limit.

Count the Number of individual digits and divide the given number into individual digits.

Calculate the power of n for each individual and add those numbers.

Compare the original value with Sum value. If they are equal then print the Number and it is Armstrong number.

Output:-

lower limit: 100 upper limit: 200 Armstrong Numbers are: 153

So Guy’s, I hope you really enjoy this tutorial and feel free to leave a comment if you have any doubt.

**You may also learn:**

- Armstrong Number Check of a given number in input using Python
- Python Program to find LCM of two numbers

## Leave a Reply