Pronic number in Python

Hi Pythoneers, In this tutorial, we will learn how to check if a number is a pronic number or not in Python.

How many of you know what is a Pronic number?

According to Wikipedia,

pronic number is a number which is the product of two consecutive integers, that is, a number of the form n(n + 1).

Pronic numbers are also known as oblong or heteromecic numbers.
In this tutorial, we will find out whether a given number is a Pronic number or not in Python.

Python Program to check pronic number

n = int(input("Enter a number: "))
f = 0
for i in range(n):
    if i * (i + 1) == n:
        f = 1
        break

if f==1:
    print("Pronic number")
else:
    print("Not a Pronic number")

Some examples of Pronic number are 0, 2, 6, 12, 20, 30, 42, 56, 72, 90, 110, 132, 156, 182, 210, 240, 272, 306, 342, 380, 420, 462 .

The above code will produce the following output:

Enter a number: 3
Not a Pronic number
Enter a number: 20
Pronic number

So here it is. A very simple program to check whether a given number is Pronic or not.

Some facts about Pronic numbers

  • The nth Pronic number is the sum of the first n even integers.

  • All Pronic numbers are even
  • 2 is the only prime Pronic number.
  • The sum of the reciprocals of Pronic numbers is 1.

 

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