Pronic number in Python
Hi Pythoneers, In this tutorial, we will learn how to check if a number is a pronic number or not in Python.
How many of you know what is a Pronic number?
According to Wikipedia,
A pronic number is a number which is the product of two consecutive integers, that is, a number of the form n(n + 1).
Pronic numbers are also known as oblong or heteromecic numbers.
In this tutorial, we will find out whether a given number is a Pronic number or not in Python.
Python Program to check pronic number
n = int(input("Enter a number: ")) f = 0 for i in range(n): if i * (i + 1) == n: f = 1 break if f==1: print("Pronic number") else: print("Not a Pronic number")
Some examples of Pronic number are 0, 2, 6, 12, 20, 30, 42, 56, 72, 90, 110, 132, 156, 182, 210, 240, 272, 306, 342, 380, 420, 462 .
The above code will produce the following output:
Enter a number: 3 Not a Pronic number
Enter a number: 20 Pronic number
So here it is. A very simple program to check whether a given number is Pronic or not.
Some facts about Pronic numbers

The nth Pronic number is the sum of the first n even integers.
 All Pronic numbers are even
 2 is the only prime Pronic number.
 The sum of the reciprocals of Pronic numbers is 1.
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