Predict Weather Report Using Machine Learning in Python
By Balender SinghIn this tutorial, we will learn how to predict the weather report using machine learning in python. In layman terms, I can simply define it as forecasting weather so I have used Time series forecasting to predict future values based on previously observed values.
Time series are widely used for non-stationary data, like economic data, weather reports, stock price, and retail sales. Let’s get started!
Predict Weather Report Using Machine Learning in Python
We are using Delhi weather data that can be downloaded from here.
Step 1:
Importing libraries
import pandas as pd #Data manipulation and analysis import numpy as np #It is utilised a number of mathematical operations import seaborn as sn #visualization import matplotlib.pyplot as plt #plotting library from datetime import datetime import statsmodels.api as sm #Conducting statistical tests from statsmodels.tsa.arima_model import ARIMA from statsmodels.tsa.stattools import adfuller, acf, pacf from statsmodels.graphics.tsaplots import plot_acf, plot_pacf import pmdarima as pm #Statistical library
Step 2:
Importing dataset
The downloaded dataset is to be placed in the directory
df = pd.read_csv('delhi.csv')Overview of the data
df.info()
<class 'pandas.core.frame.DataFrame'> RangeIndex: 100990 entries, 0 to 100989 Data columns (total 20 columns): # Column Non-Null Count Dtype --- ------ -------------- ----- 0 datetime_utc 100990 non-null object 1 _conds 100918 non-null object 2 _dewptm 100369 non-null float64 3 _fog 100990 non-null int64 4 _hail 100990 non-null int64 5 _heatindexm 29155 non-null float64 6 _hum 100233 non-null float64 7 _precipm 0 non-null float64 8 _pressurem 100758 non-null float64 9 _rain 100990 non-null int64 10 _snow 100990 non-null int64 11 _tempm 100317 non-null float64 12 _thunder 100990 non-null int64 13 _tornado 100990 non-null int64 14 _vism 96562 non-null float64 15 _wdird 86235 non-null float64 16 _wdire 86235 non-null object 17 _wgustm 1072 non-null float64 18 _windchillm 579 non-null float64 19 _wspdm 98632 non-null float64 dtypes: float64(11), int64(6), object(3) memory usage: 15.4+ MB
as we can see here we have 100990 entries and 20 columns
Now let’s see the name of the columns
df.columns
Index(['datetime_utc', ' _conds', ' _dewptm', ' _fog', ' _hail',
' _heatindexm', ' _hum', ' _precipm', ' _pressurem', ' _rain', ' _snow',
' _tempm', ' _thunder', ' _tornado', ' _vism', ' _wdird', ' _wdire',
' _wgustm', ' _windchillm', ' _wspdm'],
dtype='object')Step 3:
Pre-processing and EDA(exploratory data analysis)
now let’s look for the missing values first because missing values can influence our outcome.
plt.figure(figsize=(8,8))
sns.barplot(x = df.count()[:],y = df.count().index)
plt.xlabel('Non null values count')
plt.ylabel('features')Text(0, 0.5, 'features')
Now we can see that there are missing values in every column so now we are going to consider only a few of the columns which seem important for our basic EDA
df = df.drop([' _dewptm',' _fog',' _hail',' _heatindexm',' _pressurem',' _precipm',' _rain',' _snow',' _thunder',' _tornado',' _vism',' _wdird',' _wdire',' _wgustm',' _windchillm',' _wspdm'],axis=1)
df.head()
| datetime_utc | _conds | _hum | _tempm | |
|---|---|---|---|---|
| 0 | 19961101-11:00 | Smoke | 27.0 | 30.0 |
| 1 | 19961101-12:00 | Smoke | 32.0 | 28.0 |
| 2 | 19961101-13:00 | Smoke | 44.0 | 24.0 |
| 3 | 19961101-14:00 | Smoke | 41.0 | 24.0 |
| 4 | 19961101-16:00 | Smoke | 47.0 | 23.0 |
Now we can see that the date-time column is not in the desired format. So first, we will convert it into the desired format (YYYY-MM-DD HH: MM) And then we will make that column the index of the data
df['datetime_utc'] = pd.to_datetime(df['datetime_utc'].apply(lambda x: datetime.strptime(x,"%Y%m%d-%H:%M").strftime("%Y-%m-%d %H:%M")))
df['datetime_utc'].head()0 1996-11-01 11:00:00 1 1996-11-01 12:00:00 2 1996-11-01 13:00:00 3 1996-11-01 14:00:00 4 1996-11-01 16:00:00 Name: datetime_utc, dtype: datetime64[ns]
# as we can see on the above table datatime_utc is column so we have to convert this to index
df = df.set_index('datetime_utc',drop = True)
df.index.name = 'datetime'
df.info()<class 'pandas.core.frame.DataFrame'> DatetimeIndex: 100990 entries, 1996-11-01 11:00:00 to 2017-04-24 18:00:00 Data columns (total 3 columns): # Column Non-Null Count Dtype --- ------ -------------- ----- 0 condition 100918 non-null object 1 humidity 100233 non-null float64 2 temprature 100317 non-null float64 dtypes: float64(2), object(1) memory usage: 3.1+ MB
for easy understanding, we are going to change the names of the remaining columns
df = df.rename(index = str, columns={' _conds':'condition',' _hum':'humidity',' _tempm':'temperature'})
df.head()| datetime_utc | condition | humidity | temperature | |
|---|---|---|---|---|
| 0 | 1996-11-01 11:00:00 | Smoke | 27.0 | 30.0 |
| 1 | 1996-11-01 12:00:00 | Smoke | 32.0 | 28.0 |
| 2 | 1996-11-01 13:00:00 | Smoke | 44.0 | 24.0 |
| 3 | 1996-11-01 14:00:00 | Smoke | 41.0 | 24.0 |
| 4 | 1996-11-01 16:00:00 | Smoke | 47.0 | 23.0 |
we have fixed the Index issue, name of the columns and changed the date-time formate.
let’s fix the null values now
df.isnull().sum()
condition 72 humidity 757 temperature 673 dtype: int64
we will use mean to replace missing values in humidity and temperature
df.fillna(df.mean(), inplace=True) df.isnull().sum()
condition 72 humidity 0 temperature 0 dtype: int64
We have fixed the missing values of humidity and temperature, let’s fix the condition we have to use the front fit method for this Categorical variable
df.ffill(inplace=True) df[df.isnull()].count()
condition 0 humidity 0 temprature 0 dtype: int64
let’s visualize conditions
weather_condition = (df.condition.value_counts()/(df.condition.value_counts().sum())) * 100
weather_condition.plot.bar(figsize=(16,9))
plt.xlabel('Weather Conditions')
plt.ylabel('Percent')
We can see that the weather condition mostly is haze and smoke this is all due to pollution
Now we have to set the frequency to the date-time index or else this will make errors in the future and one more thing that the code below removes all the categorical variables(i.e conditions) and I don’t need the categorical variable so I’m just ok with this.
df = df.resample('H').mean().interpolate()
df.info()<class 'pandas.core.frame.DataFrame'> DatetimeIndex: 179504 entries, 1996-11-01 11:00:00 to 2017-04-24 18:00:00 Freq: H Data columns (total 2 columns): # Column Non-Null Count Dtype --- ------ -------------- ----- 0 humidity 179504 non-null float64 1 temperature 179504 non-null float64 dtypes: float64(2) memory usage: 4.1 MB
We can see that the categorical variable condition is not here and the frequency is added to the Date-time index
Let’s find out outliers in our data. I have used here describe method to check for outliers we can also use box plot to identify
df.describe()
| humidity | temperature | |
|---|---|---|
| count | 179504.000000 | 179504.000000 |
| mean | 58.425165 | 25.065563 |
| std | 23.465756 | 8.266500 |
| min | 4.000000 | 1.000000 |
| 25% | 40.000000 | 19.000000 |
| 50% | 59.000000 | 26.867000 |
| 75% | 78.000000 | 31.000000 |
| max | 243.000000 | 90.000000 |
It is showing maximum temperature as 90 and max humidity as 243 which is non-realistic, so it is an outlier. We need to treat these outliers.
df = df[df.temperature < 50] df = df[df.humidity <= 100] df.describe()
| humidity | temperature | |
|---|---|---|
| count | 179488.000000 | 179488.000000 |
| mean | 58.422029 | 25.063841 |
| std | 23.452692 | 8.262075 |
| min | 4.000000 | 1.000000 |
| 25% | 40.000000 | 19.000000 |
| 50% | 59.000000 | 26.861713 |
| 75% | 78.000000 | 31.000000 |
| max | 100.000000 | 48.333333 |
now let’s plot humidity and temperature
df.plot(subplots = True , figsize= (15,6))
array([<matplotlib.axes._subplots.AxesSubplot object at 0x0000028B5410A248>,
<matplotlib.axes._subplots.AxesSubplot object at 0x0000028B5412D8C8>],
dtype=object)
df['2015':'2016'].resample('D').fillna(method='pad').plot(subplots=True, figsize=(20,12))array([<matplotlib.axes._subplots.AxesSubplot object at 0x0000028B54D87C08>,
<matplotlib.axes._subplots.AxesSubplot object at 0x0000028B54F95648>],
dtype=object)![df['2015':'2016'].resample('D').fillna(method='pad').plot(subplots=True, figsize=(20,12))](https://cdn.codespeedy.com/wp-content/uploads/2020/04/04.png)
The humidity is lower between April and July and the temperature is greater in the mid two quarter
Step 4:
Model building
Let’s decompose the time series to visualize trend, season and noise separately
train = df[:'2015']
test = df['2016':]
def decomposeNplot(data):
decomposition = sm.tsa.seasonal_decompose(data)
plt.figure(figsize=(15,16))
ax1 = plt.subplot(411)
decomposition.observed.plot(ax=ax1)
ax1.set_ylabel('Observed')
ax2 = plt.subplot(412)
decomposition.trend.plot(ax=ax2)
ax2.set_ylabel('Trend')
ax3 = plt.subplot(413)
decomposition.seasonal.plot(ax=ax3)
ax3.set_ylabel('Seasonal')
ax4 = plt.subplot(414)
decomposition.resid.plot(ax=ax4)
ax4.set_ylabel('Residuals')
return decomposition
# Resampling the data to mothly and averaging out the temperature & we will predict the monthly average temperature
ftraindata = train['temperature'].resample('M').mean()
ftestdata = test['temperature'].resample('M').mean()
# Taking the seasonal difference S=12 and decomposing the timeseries
decomposition = decomposeNplot(ftraindata.diff(12).dropna())
results = adfuller(ftraindata.diff(12).dropna()) results
(-3.789234435915501,
0.0030194014111634623,
14,
203,
{'1%': -3.462980134086401,
'5%': -2.875885461947131,
'10%': -2.5744164898444515},
738.4331626389505)p-value <= 0.05: Reject the null hypothesis (H0), the data does not have a unit root and is stationary
We observed before that there is a yearly periodic pattern -> Seasonal
To get non-seasonal orders of the SARIMAX Model we will first use ACF & PACF plots
plt.figure(figsize=(10,8)) ax1 = plt.subplot(211) acf = plot_acf(ftraindata.diff(12).dropna(),lags=30,ax=ax1) ax2 = plt.subplot(212) pacf = plot_pacf(ftraindata.diff(12).dropna(),lags=30,ax=ax2)
It's hard to get the idea of the non-seasonal orders from these plots
To get seasonal orders of the SARIMAX Model we will first use ACF & PACF plots at seasonal lags
lags = [12*i for i in range(1,4)] plt.figure(figsize=(10,8)) ax1 = plt.subplot(211) acf = plot_acf(ftraindata.diff(12).dropna(),lags=lags,ax=ax1) ax2 = plt.subplot(212) pacf = plot_pacf(ftraindata.diff(12).dropna(),lags=lags,ax=ax2)
Let’s select the best model based on the AIC scores using auto_arima
results = pm.auto_arima(ftraindata,seasonal=True, m=12,d=0,D=1,trace=True,error_action='ignore',suppress_warnings=True)
Performing stepwise search to minimize aic Fit ARIMA: (2, 0, 2)x(1, 1, 1, 12) (constant=True); AIC=746.883, BIC=773.959, Time=5.936 seconds Fit ARIMA: (0, 0, 0)x(0, 1, 0, 12) (constant=True); AIC=861.067, BIC=867.836, Time=0.063 seconds Fit ARIMA: (1, 0, 0)x(1, 1, 0, 12) (constant=True); AIC=792.173, BIC=805.711, Time=0.519 seconds Fit ARIMA: (0, 0, 1)x(0, 1, 1, 12) (constant=True); AIC=748.617, BIC=762.155, Time=2.779 seconds Near non-invertible roots for order (0, 0, 1)(0, 1, 1, 12); setting score to inf (at least one inverse root too close to the border of the unit circle: 1.000) Fit ARIMA: (0, 0, 0)x(0, 1, 0, 12) (constant=False); AIC=859.369, BIC=862.753, Time=0.059 seconds Fit ARIMA: (2, 0, 2)x(0, 1, 1, 12) (constant=True); AIC=746.155, BIC=769.847, Time=4.267 seconds Near non-invertible roots for order (2, 0, 2)(0, 1, 1, 12); setting score to inf (at least one inverse root too close to the border of the unit circle: 1.000) Fit ARIMA: (2, 0, 2)x(1, 1, 0, 12) (constant=True); AIC=796.814, BIC=820.506, Time=2.523 seconds Fit ARIMA: (2, 0, 2)x(2, 1, 1, 12) (constant=True); AIC=748.988, BIC=779.449, Time=14.277 seconds Near non-invertible roots for order (2, 0, 2)(2, 1, 1, 12); setting score to inf (at least one inverse root too close to the border of the unit circle: 1.000) Fit ARIMA: (2, 0, 2)x(1, 1, 2, 12) (constant=True); AIC=749.082, BIC=779.542, Time=14.701 seconds Near non-invertible roots for order (2, 0, 2)(1, 1, 2, 12); setting score to inf (at least one inverse root too close to the border of the unit circle: 1.000) Fit ARIMA: (2, 0, 2)x(0, 1, 0, 12) (constant=True); AIC=850.698, BIC=871.005, Time=1.009 seconds Fit ARIMA: (2, 0, 2)x(0, 1, 2, 12) (constant=True); AIC=748.537, BIC=775.613, Time=15.565 seconds Near non-invertible roots for order (2, 0, 2)(0, 1, 2, 12); setting score to inf (at least one inverse root too close to the border of the unit circle: 1.000) Fit ARIMA: (2, 0, 2)x(2, 1, 0, 12) (constant=True); AIC=778.693, BIC=805.769, Time=3.744 seconds Fit ARIMA: (2, 0, 2)x(2, 1, 2, 12) (constant=True); AIC=750.709, BIC=784.554, Time=12.544 seconds Near non-invertible roots for order (2, 0, 2)(2, 1, 2, 12); setting score to inf (at least one inverse root too close to the border of the unit circle: 1.000) Fit ARIMA: (1, 0, 2)x(1, 1, 1, 12) (constant=True); AIC=746.534, BIC=770.226, Time=3.604 seconds Near non-invertible roots for order (1, 0, 2)(1, 1, 1, 12); setting score to inf (at least one inverse root too close to the border of the unit circle: 1.000) Fit ARIMA: (2, 0, 1)x(1, 1, 1, 12) (constant=True); AIC=744.691, BIC=768.382, Time=3.829 seconds Near non-invertible roots for order (2, 0, 1)(1, 1, 1, 12); setting score to inf (at least one inverse root too close to the border of the unit circle: 1.000) Fit ARIMA: (3, 0, 2)x(1, 1, 1, 12) (constant=True); AIC=743.924, BIC=774.385, Time=2.851 seconds Near non-invertible roots for order (3, 0, 2)(1, 1, 1, 12); setting score to inf (at least one inverse root too close to the border of the unit circle: 1.000) Fit ARIMA: (2, 0, 3)x(1, 1, 1, 12) (constant=True); AIC=750.534, BIC=780.995, Time=3.040 seconds Near non-invertible roots for order (2, 0, 3)(1, 1, 1, 12); setting score to inf (at least one inverse root too close to the border of the unit circle: 1.000) Fit ARIMA: (1, 0, 1)x(1, 1, 1, 12) (constant=True); AIC=744.620, BIC=764.927, Time=1.428 seconds Near non-invertible roots for order (1, 0, 1)(1, 1, 1, 12); setting score to inf (at least one inverse root too close to the border of the unit circle: 1.000) Fit ARIMA: (1, 0, 3)x(1, 1, 1, 12) (constant=True); AIC=748.493, BIC=775.569, Time=1.454 seconds Near non-invertible roots for order (1, 0, 3)(1, 1, 1, 12); setting score to inf (at least one inverse root too close to the border of the unit circle: 1.000) Fit ARIMA: (3, 0, 1)x(1, 1, 1, 12) (constant=True); AIC=748.466, BIC=775.542, Time=1.826 seconds Near non-invertible roots for order (3, 0, 1)(1, 1, 1, 12); setting score to inf (at least one inverse root too close to the border of the unit circle: 1.000) Fit ARIMA: (3, 0, 3)x(1, 1, 1, 12) (constant=True); AIC=752.426, BIC=786.271, Time=2.774 seconds Near non-invertible roots for order (3, 0, 3)(1, 1, 1, 12); setting score to inf (at least one inverse root too close to the border of the unit circle: 1.000) Total fit time: 98.833 seconds
Fitting the ARIMA model
mod = sm.tsa.statespace.SARIMAX(ftraindata,
order=(3, 0, 3),
seasonal_order=(1, 1, 1, 12),
enforce_stationarity=False,
enforce_invertibility=False)
results = mod.fit()
print(results.summary()) SARIMAX Results
============================================================================================
Dep. Variable: temperature No. Observations: 230
Model: SARIMAX(3, 0, 3)x(1, 1, [1], 12) Log Likelihood -338.758
Date: Thu, 16 Apr 2020 AIC 695.515
Time: 16:54:34 BIC 725.290
Sample: 11-30-1996 HQIC 707.562
- 12-31-2015
Covariance Type: opg
==============================================================================
coef std err z P>|z| [0.025 0.975]
------------------------------------------------------------------------------
ar.L1 0.1548 1.185 0.131 0.896 -2.168 2.477
ar.L2 0.5894 0.494 1.192 0.233 -0.380 1.558
ar.L3 -0.3190 0.596 -0.535 0.593 -1.487 0.849
ma.L1 0.2347 1.193 0.197 0.844 -2.103 2.573
ma.L2 -0.5308 0.936 -0.567 0.570 -2.365 1.303
ma.L3 0.2525 0.346 0.730 0.465 -0.425 0.930
ar.S.L12 -0.0585 0.091 -0.644 0.520 -0.237 0.120
ma.S.L12 -0.8759 0.088 -9.918 0.000 -1.049 -0.703
sigma2 1.4823 0.202 7.337 0.000 1.086 1.878
===================================================================================
Ljung-Box (Q): 38.72 Jarque-Bera (JB): 20.19
Prob(Q): 0.53 Prob(JB): 0.00
Heteroskedasticity (H): 0.53 Skew: -0.23
Prob(H) (two-sided): 0.01 Kurtosis: 4.48
===================================================================================
Warnings:
[1] Covariance matrix calculated using the outer product of gradients (complex-step).let’s diagnose the results
results.plot_diagnostics(figsize=(16, 8)) plt.show()
Here we can see:
Standardized residual plot: No obvious structure ✔
Histogram & KDE: KDE is normally distributed ✔
Normal Q-Q: Almost all the points are on the red line ✔
Correlogram of residuals: is nearly zero for all lags ✔
Mean Absolute Error for training data
print(np.mean(np.abs(results.resid)))
~2 *C monthly average temperature error
Step 5:
Forecasting
forecast = results.get_forecast(steps=len(ftestdata))
predictedmean = forecast.predicted_mean bounds = forecast.conf_int() lower_limit = bounds.iloc[:,0] upper_limit = bounds.iloc[:,1]
plt.figure(figsize=(15,7))
plt.plot(ftraindata.index, ftraindata, label='train')
plt.plot(ftestdata.index,ftestdata,label='actual')
plt.plot(predictedmean.index, predictedmean, color='r', label='forecast')
plt.fill_between(lower_limit.index,lower_limit,upper_limit, color='pink')
plt.xlabel('Date')
plt.ylabel('Delhi Temperature')
plt.legend()
plt.show()
#Producing and visualizing forecast
pred_uc = results.get_forecast(steps=100)
pred_ci = pred_uc.conf_int()
ax = ftraindata.plot(label='observed', figsize=(14, 7))
pred_uc.predicted_mean.plot(ax=ax, label='Forecast')
ax.fill_between(pred_ci.index,
pred_ci.iloc[:, 0],
pred_ci.iloc[:, 1], color='k', alpha=.25)
ax.set_xlabel('Date')
ax.set_ylabel('Delhi Temprature')
plt.legend()
plt.show()
Step 6:
Saving the model for future reference
import joblib joblib.dump(forecast,'finalized_model.pkl')
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