Initialize List of Size N in Python
Sometimes while working on a project, when there is a need to work on lists and their sub-topics, we need to know how to initialize a list of size n. We can do this through two methods:
- By creating an empty list of size n.
Let’s try to implement the above two methods-
Create an empty list of size n in Python
Here we will declare a list of size n with all the elements as zero and then we can update the elements using the index.
The value of n can be anything. Here’s the snippet part-
[0, 0, 0, 0, 0, 0, 0, 0, 0]
We have created an empty list of size n in Python. Now we can change/modify the values in the list using the index value.
We can do the same for a 2-d array in Python as-
n=5 list=[*n]*n print(list)
[[0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0]]
Create a list of size n using range() in Python
Now we will move forward to the next method of creating a list of size n in Python using
range() function in Python. It is so easy, we just need to run a for loop, under which we will use the condition up to n. It can also be helpful when we need a sequence of numbers in the list.
Here’s the simple program to implement-
[1, 2, 3, 4]
In the second method, we have used range() function to create a sequential list of size n.
You can check: range() vs xrange() in Python with examples
We have discussed two ways for creating a list of size n which first creates an empty list of size n and then creates a 2-d list of size n. The second method creates a sequential list of size n in Python.