Delete Row from NumPy Array that contains a specific value
In this tutorial, we will be learning how to delete a row from Numpy array that contains a specific value in Python. (Numerical Python).
You may be thinking, “This looks so easy”. Yes, You may feel that way but it is a bit tricky while programming and for that, you need to be aware of some NumPy array functions. If you are not aware, relax, because I will cover those for you. So let’s get started.
Remove row from NumPy Array containing a specific value in Python
First of all, we need to import NumPy in order to perform the operations.
import numpy as np
You may or may not write “as Your_name“. It is done so that we do not have to write numpy again and again in our code. Your_name can be anything you like.
Next, Using numpy, we need to create a 2D array, which is nothing but multiple lists and we need to store our array in a variable let’s say arr.
array() is a function used to create array which contains multiple lists separated by comma. If you do not know about creating 2D lists in python, learn here.
Now, lets declare a variable var that contains the value whose row is to be deleted.
Now, We need to iterate the array arr to find our value inside it. This can be done as follows.
for i in range(0,2): for x in arr[i]: if(x==val):
After we find the value, we need to delete the containing row. For that, we use delete() function that takes 3 arguments.
- Index of containing list.
- axis (If we do not mention axis then our list gets flattened i.e, Converts into 1D array)
if axis=0, it means we are choosing row-wise deletion and if axis=1, then it means column wise deletion.
Let’s see how to do it.
We modified our existing array arr with the new array which does not has the row containing the value var=3.
Alternatively, you can name your new array something else.
So, now we have an array which does not has the row containing the value 3
finally, we print our array to see the required output.
Let’s see how our code looks like.
import numpy as np arr=np.array([[1,2,3],[4,5,6],[7,8,9]]) val=3 for i in range(0,2): for x in arr[i]: if(x==val): arr=np.delete(arr,i,0) print(arr)
[[4 5 6] [7 8 9]]
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