# C++ Program to remove only the tenth digit of the number

In this tutorial, we will learn how to **remove only the tenth digit** of a number in C++.

This program **removes only the tenth digit** of the integer.

## How to put an integer into an array?

int number; cin>>number; int temp_hold=number; int array[100],count=0; while(temp_hold!=0){ array[count]=temp_hold%10; count++; temp_hold/=10; }

In the above code, the integer is assigned to the variable name number.

- The array[100] is declared to hold each values of the integer. The variable ‘count’ initialised with 0 monitors the index position.
- The temp_hold is a variable holding the integer number.
- While loop works until the temp_hold is equal to zero.
- array[0] now holds last digit of the integer , temp_val %10 gets only the last digit.
- The count is now incremented and the array[0] becomes array[1] and so on.
- temp_hold=temp_hold/10 operation is performed to avoid infinite loop to occur.
- The while loop executes until all the digits are stored into the array.

### How to find the tenth digit if the integer is a single digit?

This problem is also solved in this program. Here we are maintaining a count variable to put the digit into the array.

The count is checked whether it is greater than 1 if not then the value is directly printed denoting , there is no tenth digit in the integer.

**INPUT 1:**

Enter the number:

1234

## C++ code to remove only the tenth digit of a number

#include<iostream.h> using namespace std; int main(){ cout<<"Enter the number:"<<"\n"; int number; cin>>number; int temp_hold=number; int array1[100],array2[100],index=0,count=0,ind=0; int temp_var=number; //To find the number of digits in the number// while(temp_hold!=0){ temp_hold/=10; count++; } if(count>1){ cout<<"The number after removing only the tenth digit:"<<"\t"; while(temp_var!=0){ array1[index]=temp_var%10; index++; if(index==1){ temp_var/=10; } temp_var/=10; } if(index>=1){ for(int i=index-1;i>=0;i--){ array2[ind]=array1[i]; ind++; } } for(int i=0;i<ind;i++){ cout<<array2[i]; } } else{ cout<<"The number does not have tenth digit."; } }

In the above code,

- The index value is incremented every time and the digits are stored into the array simultaneously.
- The count if it is greater than 1 then it is sure that the number is having tenth digit which can be removed.
- The while loop is executed until temp_var is equal 0.
- The array1[index] stores from the last digit and simultaneously if the index value is equal to 1 the temp_var is divided by 10 to avoid infinite loop.
- The array1[] contains the digits in the reverse order.
- The array2[ind] is declared with ind=0 as index position.
- The for loop is initialised from index1-1 and the condition ends if it is equal to 0 and decremented.
- The array2[] starts holding the values of array1[] in the reverse order until the for loop is terminated.
- The array2 now contains the number without
**the tenth digit**and it is printed. - If the count of digits in the number is 1 , the else segment is executed which prints the number.

**OUTPUT 1:**

The number after removing only the tenth digit : 124

**INPUT 2 :**

Enter the number : 3

**OUTPUT 2:**

The number does not have tenth digit.

This program **removes only the tenth digit** of the number.

We hope this tutorial helped you to understand how to remove only the tenth digit of the number.

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