# C++ Program to remove only the tenth digit of the number

In this tutorial, we will learn how to remove only the tenth digit of a number in C++.

This program removes only the tenth digit of the integer.

## How to put an integer into an array?

```int number;
cin>>number;
int temp_hold=number;
int array,count=0;
while(temp_hold!=0){
array[count]=temp_hold%10;
count++;
temp_hold/=10;
}```

In the above code, the integer is assigned to the variable name number.

• The array is declared to hold each values of the integer. The variable ‘count’ initialised with 0 monitors the index position.
• The temp_hold is a variable holding the integer number.
• While loop works until the temp_hold is equal to zero.
• array now holds last digit of the integer , temp_val %10 gets only the last digit.
• The count is now incremented and the array becomes array and so on.
• temp_hold=temp_hold/10 operation is performed to avoid infinite loop to occur.
• The while loop executes until all the digits are stored into the array.

### How to find the tenth digit if the integer is a single digit?

This problem is also solved in this program. Here we are maintaining a count variable to put the digit into the array.

The count is checked whether it is greater than 1 if not then the value is directly printed denoting , there is no tenth digit in the integer.

INPUT 1:

Enter the number:

1234

## C++ code to remove only the tenth digit of a number

```#include<iostream.h>
using namespace std;
int main(){
cout<<"Enter the number:"<<"\n";
int number;
cin>>number;
int temp_hold=number;
int array1,array2,index=0,count=0,ind=0;
int temp_var=number;
//To find the number of digits in the number//
while(temp_hold!=0){
temp_hold/=10;
count++;
}
if(count>1){
cout<<"The number after removing only the tenth digit:"<<"\t";
while(temp_var!=0){
array1[index]=temp_var%10;
index++;
if(index==1){
temp_var/=10;
}
temp_var/=10;
}
if(index>=1){
for(int i=index-1;i>=0;i--){
array2[ind]=array1[i];
ind++;
}
}
for(int i=0;i<ind;i++){
cout<<array2[i];
}
}
else{
cout<<"The number does not have tenth digit.";
}
}```

In the above code,

• The index value is incremented every time and the digits are stored into the array simultaneously.
• The count if it is greater than 1 then it is sure that the number is having tenth digit which can be removed.
• The while loop is executed until temp_var is equal 0.
• The array1[index] stores from the last digit and simultaneously if the index value is equal to 1 the temp_var is divided by 10 to avoid infinite loop.
• The array1[] contains the digits in the reverse order.
• The array2[ind] is declared with ind=0 as index position.
• The for loop is initialised from index1-1 and the condition ends if it is equal to 0 and decremented.
• The  array2[] starts holding the values of array1[] in the reverse order until the for loop is terminated.
• The array2 now contains the number without the tenth digit and it is printed.
• If the count of digits in the number is 1 , the else segment is executed which prints the number.

OUTPUT 1:

`The number after removing only the tenth digit :  124`

INPUT 2 :

`Enter the number : 3`

OUTPUT 2:

`The number does not have tenth digit.`

This program removes only the tenth digit of the number.

We hope this tutorial helped you to understand how to remove only the tenth digit of the number.

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