Hurst exponent in Python

By Karun Thannickal

In this tutorial, we will learn about using the Hurst exponent in Python. The Hurst exponent is a useful parameter in dealing with time-series. It is a measure of a time-series to .... Read More

CamelCase pattern matching in C++

By Pratik Tayade

In this tutorial, we are going to discuss the CamelCase pattern matching in C++. Before moving towards CamelCase programming, first, we need to understand what is CamelCase? CamelC.... Read More

std::get_temporary_buffer in C++

By Vishal Patil

Hello everyone, in this tutorial, we will learn about the get_temporary_buffer in C++. std::get_temporary_buffer Generally, buffer refers to a block of computer memory that serves .... Read More

C++ Program to find if the strings can be chained to form a circle

By Nishant Saxena

So, we’ll discuss how an array/vector of strings in C++ can be chained together to form a circle or loop. So to start with it lets first understand the topic. Chain of String.... Read More

Define and use Tensors using Simple Tensorflow Examples

By Kuldeep Singh

Hello coders, in this post we will discuss Tensor and we will also see how to use them. What is TensorFlow? In Python for mathematical problems we used the TensorFlow library, it i.... Read More

Weather Forecasting Android App using OpenWeatherMap API in Android Studio

By Kamalpreet Singh

In this tutorial, we will create a Weather Forecasting application in android using java. We can create an android project either using Android Studio or Eclipse IDE. For using Ecl.... Read More

Character and Byte Streams in Java : Differences

By Niwedita Kumari

In this tutorial, we will be looking up for the wide variations between character stream and byte stream in Java. We know that stream is a sequence of data stored in a file.  Java.... Read More

C++ program to find pair with greatest product in array

By Amit Raja Kalidindi

In this tutorial, we are going to learn how to find a pair with the greatest product in an array in C++. Naive Solution: The simple solution is to consider all the possible pairs a.... Read More